Mole Concept NEET PYQ Analysis: Stoichiometry Questions That Repeat

Mole Concept is the first chapter of Class 11 Chemistry, and almost every numerical in Physical Chemistry depends on it. This mole concept NEET PYQ analysis shows which question types NTA repeats, the few formulas that solve them, and the small mistakes that cost students marks year after year.

Mole concept NEET PYQ analysis with a laboratory balance and one-mole samples of different substances

For the full plan, start with our complete physical chemistry guide and use this article for chapter-level detail.

Want to test yourself first? Solve the Some Basic Concepts of Chemistry PYQs for free, then use this guide to fix the gaps.

Why Mole Concept Matters So Much

NEET usually asks one to two direct questions from this chapter, which NCERT calls “Some Basic Concepts of Chemistry”. But the real value is bigger. Moles, molarity and stoichiometry are used inside questions from Solutions, Equilibrium, Electrochemistry and Thermodynamics.

So a weak base here quietly costs marks across Physical Chemistry. See where the chapter sits in the NEET 2027 chapter weightage, and find every Chemistry unit in our full Chemistry chapter list.

Mole Concept NEET PYQ Analysis: The Five Repeated Question Types

When you sort a decade of NEET chemistry PYQs from this chapter, five question types cover almost everything.

Question typeFrequencyWhat it tests
Mole–mass–particle conversionsMost frequentNumber of atoms, molecules or ions in a given mass or volume
Stoichiometry and limiting reactantVery frequentAmount of product formed from given reactants
Concentration termsVery frequentMolarity, molality, mole fraction, dilution
Empirical and molecular formulaRegularFormula from percentage composition
Laws of chemical combinationOccasionalLaw of multiple proportions, Avogadro’s law

Stoichiometry questions and conversions lead every year. For a quick warm-up before the full set, try these five quick mole concept questions.

The Core Conversions

Almost every question starts with finding moles. Learn these three routes:

  • From mass: moles = given mass / molar mass
  • From particles: moles = number of particles / 6.022 × 10²³
  • From gas volume at STP: moles = volume in litres / 22.4

Then remember the two-step idea: moles of molecules × atoms per molecule = moles of atoms. Most “which has the maximum number of atoms” questions are solved this way. The same step-by-step habit helps in the next chapter too, as our Structure of Atom PYQ patterns article shows. Our list of the most repeated NEET topics shows how often this pattern returns.

Stoichiometry and Limiting Reagent

A balanced equation gives the mole ratio. Follow the same four steps every time:

  1. Write the balanced equation.
  2. Convert every given quantity into moles.
  3. Divide each reactant’s moles by its coefficient. The smallest value shows which reactant runs out first.
  4. Use that reactant to find the amount of product.

This reactant decides how much product forms. The other reactant is left over as excess. Skipping step 3 is the most common reason for wrong answers in this chapter.

Concentration Terms: Molarity and Molality

TermFormulaDepends on temperature?
Molarity (M)moles of solute / volume of solution in litresYes
Molality (m)moles of solute / mass of solvent in kgNo
Mole fraction (x)moles of component / total molesNo

For dilution, use M₁V₁ = M₂V₂. The two are easy to mix up, so check the denominator: molarity uses litres of solution, while molality uses kilograms of solvent.

Empirical and Molecular Formula

  1. Divide each percentage by the element’s atomic mass.
  2. Divide all the results by the smallest value.
  3. Round to whole numbers to get the empirical formula.
  4. Molecular formula = empirical formula × n, where n = molar mass / empirical formula mass.

Worked PYQ-Pattern Questions

Q1. How many molecules are present in 4.4 g of CO₂?

Answer: 6.022 × 10²² molecules. Moles = 4.4/44 = 0.1, so molecules = 0.1 × 6.022 × 10²³.

Q2. 10 g of H₂ reacts with 64 g of O₂ to form water. What mass of water is formed?

Answer: 72 g. H₂ = 5 mol and O₂ = 2 mol. From 2H₂ + O₂ → 2H₂O, 2 mol of O₂ needs only 4 mol of H₂, so O₂ runs out first. Water formed = 4 mol = 72 g.

Q3. A compound contains 40% carbon, 6.67% hydrogen and 53.33% oxygen. What is its empirical formula?

Answer: CH₂O. Mole ratio = 40/12 : 6.67/1 : 53.33/16 = 3.33 : 6.67 : 3.33 = 1 : 2 : 1.

Q4. What is the molarity of a solution containing 4 g of NaOH in 250 mL of solution?

Answer: 0.4 M. Moles = 4/40 = 0.1, and 0.1/0.25 L = 0.4 M.

Q5. Which has the largest number of atoms: 1 g of Au, 1 g of Na, 1 g of Li or 1 g of Cl₂?

Answer: 1 g of Li. For the same mass, the element with the smallest atomic mass has the most atoms. Lithium (7) is the lightest of the four.

Common Traps in This Chapter

  • Solving for product without checking which reactant runs out first
  • Mixing up atoms and molecules in counting questions
  • Using millilitres instead of litres in molarity
  • Using 22.4 L for a liquid or solid, or for a gas that is not at STP
  • Confusing the denominators of the two concentration terms

Practise Every Mole Concept PYQ

This mole concept NEET PYQ analysis gives you the patterns. Solving real past questions builds the speed. Every previous year question from this chapter is available chapter-wise, free:

👉 Solve all Some Basic Concepts of Chemistry NEET PYQs

Write “find moles first” at the top of your rough sheet for every question. It prevents most errors.

Conclusion

Mole Concept has few formulas, but they sit behind half of Physical Chemistry. Use this mole concept NEET PYQ analysis to master conversions, the limiting reactant method and concentration terms. Then practise until finding moles becomes automatic.

❓ FAQ

Q: How many questions come from Mole Concept in NEET? A: Usually one to two direct questions. Its ideas are also used inside numericals from Solutions, Equilibrium and Electrochemistry.

Q: Is Mole Concept the same as Some Basic Concepts of Chemistry? A: Yes. NCERT names the chapter “Some Basic Concepts of Chemistry”, and students commonly call it Mole Concept.

Q: How do I find the limiting reagent quickly? A: Convert each reactant to moles and divide by its coefficient in the balanced equation. The reactant with the smallest value is the one that limits the product.

Q: What is the difference between molarity and molality? A: Molarity is moles of solute per litre of solution and changes with temperature. Molality is moles of solute per kilogram of solvent and does not change with temperature.

Q: Do Mole Concept PYQs repeat in NEET? A: The exact numbers change, but the question types repeat every year. A mole concept NEET PYQ analysis shows these patterns clearly.

Q: Where can I practise Mole Concept NEET PYQs for free? A: You can solve every previous year question from this chapter for free using the practice link in this article.

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