{"id":4609,"date":"2026-04-11T12:16:17","date_gmt":"2026-04-11T12:16:17","guid":{"rendered":"https:\/\/ksquareinstitute.in\/blog\/?p=4609"},"modified":"2026-04-11T12:16:18","modified_gmt":"2026-04-11T12:16:18","slug":"physics-electrostatics-pyqs-notes","status":"publish","type":"post","link":"https:\/\/ksquareinstitute.in\/blog\/physics-electrostatics-pyqs-notes\/","title":{"rendered":"Top PYQs from Electrostatics with Concepts & Quick Notes for NEET"},"content":{"rendered":"\n

Electrostatics is one of the most fundamental and high-weightage chapters in NEET Physics. It builds the base for Current Electricity and Magnetism, and questions are mostly concept-driven with direct formula applications. If you regularly practice Physics Electrostatics PYQs Notes<\/strong>, you will observe that NEET repeats similar patterns involving Coulomb\u2019s law, electric field, potential, capacitance, and energy stored.<\/p>\n\n\n\n

This article is designed as a dense revision resource<\/strong>, combining quick notes + high-quality PYQs with detailed solutions<\/strong>. Mastering Physics Electrostatics PYQs Notes<\/strong> ensures strong conceptual clarity and fast problem-solving during the exam.<\/p>\n\n\n\n

\"Physics<\/figure>\n\n\n\n

Physics Electrostatics Quick Notes<\/h1>\n\n\n\n

Before solving Physics Electrostatics PYQs Notes<\/strong>, revise these key formulas:<\/p>\n\n\n\n

    \n
  • Coulomb\u2019s Law:<\/li>\n<\/ul>\n\n\n\n

    F<\/mi>=<\/mo>k<\/mi>q<\/mi>1<\/mn><\/msub>q<\/mi>2<\/mn><\/msub><\/mrow>r<\/mi>2<\/mn><\/msup><\/mfrac><\/mrow>F = \\frac{kq_1q_2}{r^2}<\/annotation><\/semantics><\/math>F<\/mi>=<\/mo>k<\/mi>q<\/mi>1<\/mn><\/msub>q<\/mi>2<\/mn><\/msub><\/mrow>r<\/mi>2<\/mn><\/msup><\/mfrac><\/mrow>F = k\\frac{q_1 q_2}{r^2}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
      \n
    • Electric Field:<\/li>\n<\/ul>\n\n\n\n

      E<\/mi>=<\/mo>k<\/mi>q<\/mi><\/mrow>r<\/mi>2<\/mn><\/msup><\/mfrac><\/mrow>E = \\frac{kq}{r^2}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
        \n
      • Electric Potential:<\/li>\n<\/ul>\n\n\n\n

        V<\/mi>=<\/mo>k<\/mi>q<\/mi><\/mrow>r<\/mi><\/mfrac><\/mrow>V = \\frac{kq}{r}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
          \n
        • Potential Energy:<\/li>\n<\/ul>\n\n\n\n

          U<\/mi>=<\/mo>k<\/mi>q<\/mi>1<\/mn><\/msub>q<\/mi>2<\/mn><\/msub><\/mrow>r<\/mi><\/mfrac><\/mrow>U = \\frac{kq_1q_2}{r}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
            \n
          • Capacitance:<\/li>\n<\/ul>\n\n\n\n

            C<\/mi>=<\/mo>Q<\/mi>V<\/mi><\/mfrac><\/mrow>C = \\frac{Q}{V}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
              \n
            • Parallel Plate Capacitor:<\/li>\n<\/ul>\n\n\n\n

              C<\/mi>=<\/mo>\u03b5<\/mi>0<\/mn><\/msub>A<\/mi><\/mrow>d<\/mi><\/mfrac><\/mrow>C = \\frac{\\varepsilon_0 A}{d}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
                \n
              • Energy Stored:<\/li>\n<\/ul>\n\n\n\n

                U<\/mi>=<\/mo>1<\/mn>2<\/mn><\/mfrac>C<\/mi>V<\/mi>2<\/mn><\/msup><\/mrow>U = \\frac{1}{2}CV^2<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

                These formulas form the base of most Physics Electrostatics PYQs Notes<\/strong>.<\/p>\n\n\n\n

                \n\n\n\n

                Top Physics Electrostatics PYQs (With Detailed Solutions)<\/h1>\n\n\n\n
                \n\n\n\n

                1) Coulomb force<\/h2>\n\n\n\n

                Two charges 2<\/mn>\u03bc<\/mi>C<\/mi><\/mrow>2\\mu C<\/annotation><\/semantics><\/math>2\u03bcC and 3<\/mn>\u03bc<\/mi>C<\/mi><\/mrow>3\\mu C<\/annotation><\/semantics><\/math>3\u03bcC are placed 1 m apart.<\/p>\n\n\n\n

                Solution<\/h3>\n\n\n\n

                F<\/mi>=<\/mo>9<\/mn>\u00d7<\/mo>10<\/mn>9<\/mn><\/msup>\u00d7<\/mo>6<\/mn>\u00d7<\/mo>10<\/mn>\u2212<\/mo>12<\/mn><\/mrow><\/msup><\/mrow>1<\/mn><\/mfrac>=<\/mo>54<\/mn>\u00d7<\/mo>10<\/mn>\u2212<\/mo>3<\/mn><\/mrow><\/msup><\/mrow>F = \\frac{9\\times10^9 \\times 6\\times10^{-12}}{1} = 54\\times10^{-3}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

                Answer: 0.054 N<\/strong><\/p>\n\n\n\n

                \n\n\n\n

                2) Electric field due to point charge<\/h2>\n\n\n\n

                Charge 5<\/mn>\u03bc<\/mi>C<\/mi><\/mrow>5\\mu C<\/annotation><\/semantics><\/math>5\u03bcC at 2 m.<\/p>\n\n\n\n

                Solution<\/h3>\n\n\n\n

                E<\/mi>=<\/mo>9<\/mn>\u00d7<\/mo>10<\/mn>9<\/mn><\/msup>\u00d7<\/mo>5<\/mn>\u00d7<\/mo>10<\/mn>\u2212<\/mo>6<\/mn><\/mrow><\/msup><\/mrow>4<\/mn><\/mfrac>=<\/mo>11250<\/mn> N\/C<\/mtext><\/mrow>E = \\frac{9\\times10^9 \\times 5\\times10^{-6}}{4} = 11250\\text{ N\/C}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

                Answer: 11250 N\/C<\/strong><\/p>\n\n\n\n

                \n\n\n\n

                3) Potential difference<\/h2>\n\n\n\n

                Work 10 J, charge 2 C.<\/p>\n\n\n\n

                Solution<\/h3>\n\n\n\n

                V<\/mi>=<\/mo>W<\/mi>q<\/mi><\/mfrac>=<\/mo>5<\/mn> V<\/mtext><\/mrow>V = \\frac{W}{q} = 5\\text{ V}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

                Answer: 5 V<\/strong><\/p>\n\n\n\n

                \n\n\n\n

                4) Field zero between charges<\/h2>\n\n\n\n

                Two equal charges placed at ends.<\/p>\n\n\n\n

                Solution<\/h3>\n\n\n\n

                Field zero at midpoint.<\/p>\n\n\n\n

                Answer: Midpoint<\/strong><\/p>\n\n\n\n

                \n\n\n\n

                5) Potential at midpoint<\/h2>\n\n\n\n

                Opposite equal charges.<\/p>\n\n\n\n

                Solution<\/h3>\n\n\n\n

                Potentials cancel.<\/p>\n\n\n\n

                Answer: Zero<\/strong><\/p>\n\n\n\n

                \n\n\n\n

                6) Capacitance<\/h2>\n\n\n\n

                Parallel plate area 1 m\u00b2, separation 1 mm.<\/p>\n\n\n\n

                Solution<\/h3>\n\n\n\n

                C<\/mi>=<\/mo>8.85<\/mn>\u00d7<\/mo>10<\/mn>\u2212<\/mo>12<\/mn><\/mrow><\/msup><\/mrow>10<\/mn>\u2212<\/mo>3<\/mn><\/mrow><\/msup><\/mfrac>=<\/mo>8.85<\/mn>\u00d7<\/mo>10<\/mn>\u2212<\/mo>9<\/mn><\/mrow><\/msup> F<\/mtext><\/mrow>C = \\frac{8.85\\times10^{-12}}{10^{-3}} = 8.85\\times10^{-9}\\text{ F}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

                Answer: 8.85\u00d710\u221298.85\\times10^{-9}8.85\u00d710\u22129 F<\/strong><\/p>\n\n\n\n

                \n\n\n\n

                7) Energy stored<\/h2>\n\n\n\n

                Capacitor 10 \u00b5F, 10 V.<\/p>\n\n\n\n

                Solution<\/h3>\n\n\n\n

                U<\/mi>=<\/mo>1<\/mn>2<\/mn><\/mfrac>C<\/mi>V<\/mi>2<\/mn><\/msup>=<\/mo>5<\/mn>\u00d7<\/mo>10<\/mn>\u2212<\/mo>6<\/mn><\/mrow><\/msup>\u00d7<\/mo>100<\/mn>=<\/mo>5<\/mn>\u00d7<\/mo>10<\/mn>\u2212<\/mo>4<\/mn><\/mrow><\/msup><\/mrow>U = \\frac{1}{2}CV^2 = 5\\times10^{-6}\\times100 = 5\\times10^{-4}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

                Answer: 5\u00d710\u221245\\times10^{-4}5\u00d710\u22124 J<\/strong><\/p>\n\n\n\n

                \n\n\n\n

                8) Force in medium<\/h2>\n\n\n\n

                Dielectric constant 2.<\/p>\n\n\n\n

                Solution<\/h3>\n\n\n\n

                Force reduces:F<\/mi>\u2032<\/mo><\/msup>=<\/mo>F<\/mi>2<\/mn><\/mfrac><\/mrow>F’ = \\frac{F}{2}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

                Answer: Half<\/strong><\/p>\n\n\n\n

                \n\n\n\n

                9) Equipotential surface<\/h2>\n\n\n\n

                Electric field direction?<\/p>\n\n\n\n

                Solution<\/h3>\n\n\n\n

                Perpendicular to surface.<\/p>\n\n\n\n

                Answer: Perpendicular<\/strong><\/p>\n\n\n\n

                \n\n\n\n

                10) Capacitance series<\/h2>\n\n\n\n

                Two equal capacitors in series.<\/p>\n\n\n\n

                Solution<\/h3>\n\n\n\n

                C<\/mi>=<\/mo>C<\/mi>2<\/mn><\/mfrac><\/mrow>C = \\frac{C}{2}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

                Answer: C\/2<\/strong><\/p>\n\n\n\n

                \n\n\n\n

                11) Capacitance parallel<\/h2>\n\n\n\n

                Solution<\/h3>\n\n\n\n

                C<\/mi>=<\/mo>2<\/mn>C<\/mi><\/mrow>C = 2C<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

                Answer: 2C<\/strong><\/p>\n\n\n\n

                \n\n\n\n

                12) Electric field vs distance<\/h2>\n\n\n\n

                Solution<\/h3>\n\n\n\n

                E<\/mi>\u221d<\/mo>1<\/mn>r<\/mi>2<\/mn><\/msup><\/mfrac><\/mrow>E \\propto \\frac{1}{r^2}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
                \n\n\n\n

                13) Potential vs distance<\/h2>\n\n\n\n

                Solution<\/h3>\n\n\n\n

                V<\/mi>\u221d<\/mo>1<\/mn>r<\/mi><\/mfrac><\/mrow>V \\propto \\frac{1}{r}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
                \n\n\n\n

                14) Work done moving charge<\/h2>\n\n\n\n

                Solution<\/h3>\n\n\n\n

                Depends only on endpoints.<\/p>\n\n\n\n

                \n\n\n\n

                15) Energy in capacitor relation<\/h2>\n\n\n\n

                Solution<\/h3>\n\n\n\n

                U<\/mi>\u221d<\/mo>V<\/mi>2<\/mn><\/msup><\/mrow>U \\propto V^2<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
                \n\n\n\n

                Quick Revision \u2013 Physics Electrostatics PYQs Notes<\/h1>\n\n\n\n

                To revise Physics Electrostatics PYQs Notes<\/strong>, remember:F<\/mi>=<\/mo>k<\/mi>q<\/mi>1<\/mn><\/msub>q<\/mi>2<\/mn><\/msub><\/mrow>r<\/mi>2<\/mn><\/msup><\/mfrac><\/mrow>F = k\\frac{q_1q_2}{r^2}<\/annotation><\/semantics><\/math>F=kr2q1\u200bq2\u200b\u200b E<\/mi>=<\/mo>k<\/mi>q<\/mi><\/mrow>r<\/mi>2<\/mn><\/msup><\/mfrac><\/mrow>E = \\frac{kq}{r^2}<\/annotation><\/semantics><\/math>E=r2kq\u200b V<\/mi>=<\/mo>k<\/mi>q<\/mi><\/mrow>r<\/mi><\/mfrac><\/mrow>V = \\frac{kq}{r}<\/annotation><\/semantics><\/math>V=rkq\u200b C<\/mi>=<\/mo>\u03b5<\/mi>0<\/mn><\/msub>A<\/mi><\/mrow>d<\/mi><\/mfrac><\/mrow>C = \\frac{\\varepsilon_0 A}{d}<\/annotation><\/semantics><\/math>C=d\u03b50\u200bA\u200b U<\/mi>=<\/mo>1<\/mn>2<\/mn><\/mfrac>C<\/mi>V<\/mi>2<\/mn><\/msup><\/mrow>U = \\frac{1}{2}CV^2<\/annotation><\/semantics><\/math>U=21\u200bCV2<\/p>\n\n\n\n

                These formulas solve most Physics Electrostatics PYQs Notes<\/strong> instantly.<\/p>\n\n\n\n

                \n\n\n\n

                Most Important NEET Patterns<\/h1>\n\n\n\n

                From repeated trends in Physics Electrostatics PYQs Notes<\/strong>, NEET commonly asks:<\/p>\n\n\n\n

                  \n
                • Coulomb\u2019s law numericals<\/li>\n\n\n\n
                • Electric field & potential<\/li>\n\n\n\n
                • Capacitance combinations<\/li>\n\n\n\n
                • Energy stored<\/li>\n\n\n\n
                • Equipotential surfaces<\/li>\n<\/ul>\n\n\n\n

                  Practicing these Physics Electrostatics PYQs Notes<\/strong> ensures strong command over the chapter.<\/p>\n\n\n\n

                  \n\n\n\n

                  Final Takeaway<\/h1>\n\n\n\n

                  The key to mastering Physics Electrostatics PYQs Notes<\/strong> is understanding the difference between field and potential and applying formulas correctly. Most questions are direct, but require conceptual clarity.<\/p>\n\n\n\n

                  If you revise these Physics Electrostatics PYQs Notes<\/strong> properly, this chapter becomes one of the easiest scoring areas in NEET Physics.<\/p>\n\n\n\n

                  \n\n\n\n

                  FAQ \u2013 Physics Electrostatics PYQs Notes<\/h1>\n\n\n\n

                  1. Why are Physics Electrostatics PYQs Notes important?<\/h3>\n\n\n\n

                  They help identify repeated question patterns in NEET.<\/p>\n\n\n\n

                  2. Which topics are most important?<\/h3>\n\n\n\n

                  Coulomb\u2019s law, capacitance, electric field, and potential.<\/p>\n\n\n\n

                  3. How many questions come in NEET?<\/h3>\n\n\n\n

                  Usually 2\u20133.<\/p>\n\n\n\n

                  4. Is electrostatics difficult?<\/h3>\n\n\n\n

                  No, it becomes easy with practice of Physics Electrostatics PYQs Notes<\/strong>.<\/p>\n\n\n\n

                  <\/p>\n","protected":false},"excerpt":{"rendered":"

                  Electrostatics is one of the most fundamental and high-weightage chapters in NEET Physics. It builds the base for Current Electricity and Magnetism, and questions are mostly concept-driven with direct formula applications. If you regularly practice Physics Electrostatics PYQs Notes, you will observe that NEET repeats similar patterns involving Coulomb\u2019s law, electric field, potential, capacitance, and […]<\/p>\n","protected":false},"author":1,"featured_media":4610,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[70,2],"tags":[1122,1125,1119,1121,1124,1126,1120,1123,1127,1081,1118,1084],"class_list":["post-4609","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-physics","category-neet","tag-capacitance-questions-neet","tag-capacitor-combination-problems","tag-coulomb-law-numericals","tag-electric-field-problems","tag-electric-potential-numericals","tag-electrostatics-concepts-neet","tag-electrostatics-neet-questions","tag-electrostatics-quick-notes","tag-electrostatics-revision-notes","tag-neet-physics-pyq-practice","tag-physics-electrostatics-pyqs-notes","tag-physics-numericals-neet"],"blocksy_meta":{"page_structure_type":"type-1","styles_descriptor":{"styles":{"desktop":"","tablet":"","mobile":""},"google_fonts":[],"version":6}},"_links":{"self":[{"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/posts\/4609","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/comments?post=4609"}],"version-history":[{"count":1,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/posts\/4609\/revisions"}],"predecessor-version":[{"id":4611,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/posts\/4609\/revisions\/4611"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/media\/4610"}],"wp:attachment":[{"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/media?parent=4609"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/categories?post=4609"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/tags?post=4609"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}