{"id":4408,"date":"2026-04-07T08:59:38","date_gmt":"2026-04-07T08:59:38","guid":{"rendered":"https:\/\/ksquareinstitute.in\/blog\/?p=4408"},"modified":"2026-04-07T08:59:39","modified_gmt":"2026-04-07T08:59:39","slug":"top-5-p-block-questions","status":"publish","type":"post","link":"https:\/\/ksquareinstitute.in\/blog\/top-5-p-block-questions\/","title":{"rendered":"Top 5 p Block Questions for NEET (NCERT Based PYQs)"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">Top p Block Questions for NEET<\/h2>\n\n\n\n<p>The p-block elements chapter is one of the most scoring yet memory-intensive topics in NEET Chemistry. Unlike physical chemistry, this section is completely NCERT-driven, meaning most questions are either directly picked from the NCERT text or slightly modified versions of it. That is exactly why preparing the <strong>Top 5 p Block Questions<\/strong> becomes extremely important if you want to secure easy marks in NEET.<\/p>\n\n\n\n<p>In this detailed article, we will cover the <strong>Top 5 p Block Questions<\/strong> that are repeatedly asked in NEET PYQs. Along with solutions, you will also get conceptual clarity, tricks, and NCERT insights that help you retain information longer and answer questions faster.<\/p>\n\n\n\n<figure class=\"wp-block-image alignwide size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"289\" src=\"https:\/\/ksquareinstitute.in\/blog\/wp-content\/uploads\/2026\/04\/top-5-questions-for-neet-1-1024x289.png\" alt=\"Top 5 Chemical Equilibrium Questions for NEET, Top 5 Ionic Equilibrium Questions for NEET, Top 5 p Block Questions for NEET\" class=\"wp-image-4388\" srcset=\"https:\/\/ksquareinstitute.in\/blog\/wp-content\/uploads\/2026\/04\/top-5-questions-for-neet-1-1024x289.png 1024w, https:\/\/ksquareinstitute.in\/blog\/wp-content\/uploads\/2026\/04\/top-5-questions-for-neet-1-300x85.png 300w, https:\/\/ksquareinstitute.in\/blog\/wp-content\/uploads\/2026\/04\/top-5-questions-for-neet-1-768x217.png 768w, https:\/\/ksquareinstitute.in\/blog\/wp-content\/uploads\/2026\/04\/top-5-questions-for-neet-1-1536x434.png 1536w, https:\/\/ksquareinstitute.in\/blog\/wp-content\/uploads\/2026\/04\/top-5-questions-for-neet-1-2048x579.png 2048w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\">Question 1: Anomalous Behaviour of Nitrogen<\/h2>\n\n\n\n<p>Why does nitrogen show anomalous behaviour compared to other elements of group 15?<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Detailed Explanation<\/h3>\n\n\n\n<p>Nitrogen behaves differently from the rest of its group (P, As, Sb, Bi) due to three major reasons:<\/p>\n\n\n\n<p>First, nitrogen has a very small atomic size. Because of this, its electron cloud is compact, and electrons are held more tightly. This makes nitrogen less likely to expand its octet.<\/p>\n\n\n\n<p>Second, nitrogen has high electronegativity compared to other group 15 elements. This affects its bonding behavior and stability of compounds.<\/p>\n\n\n\n<p>Third, nitrogen does not have vacant d-orbitals in its valence shell. While heavier elements like phosphorus can expand their octet using d-orbitals, nitrogen cannot. This restricts nitrogen to a maximum covalency of four.<\/p>\n\n\n\n<p>Due to these reasons:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Nitrogen forms strong p\u03c0\u2013p\u03c0 multiple bonds (like N\u2261N)<\/li>\n\n\n\n<li>It does not form pentahalides (e.g., NCl\u2085 does not exist)<\/li>\n\n\n\n<li>It shows limited oxidation states compared to phosphorus<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p>Nitrogen shows anomalous behaviour due to its small size, high electronegativity, and absence of d-orbitals.<\/p>\n\n\n\n<p>This is one of the most important NCERT-based concepts in the <strong>Top 5 p Block Questions<\/strong>, and NEET often asks direct theory-based MCQs from it.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Question 2: Acidic Strength of Oxides<\/h2>\n\n\n\n<p>Arrange the following oxides in increasing order of acidic strength:<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mi>S<\/mi><mi>i<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><mo separator=\"true\">,<\/mo><mtext>\u2005\u200a<\/mtext><mi>C<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><mo separator=\"true\">,<\/mo><mtext>\u2005\u200a<\/mtext><mi>S<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><mo separator=\"true\">,<\/mo><mtext>\u2005\u200a<\/mtext><msub><mi>P<\/mi><mn>2<\/mn><\/msub><msub><mi>O<\/mi><mn>5<\/mn><\/msub><\/mrow><annotation encoding=\"application\/x-tex\">SiO_2, \\; CO_2, \\; SO_2, \\; P_2O_5<\/annotation><\/semantics><\/math>SiO2\u200b,CO2\u200b,SO2\u200b,P2\u200bO5\u200b<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Detailed Explanation<\/h3>\n\n\n\n<p>The acidic nature of oxides depends mainly on two factors:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Non-metallic character of the element<\/li>\n\n\n\n<li>Oxidation state of the central atom<\/li>\n<\/ul>\n\n\n\n<p>As we move across a period from left to right, non-metallic character increases, and hence acidity of oxides also increases.<\/p>\n\n\n\n<p>Also, higher oxidation states generally correspond to stronger acidic oxides.<\/p>\n\n\n\n<p>Now analyzing each compound:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mi>S<\/mi><mi>i<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><\/mrow><annotation encoding=\"application\/x-tex\">SiO_2<\/annotation><\/semantics><\/math>SiO2\u200b: Weakly acidic (network solid, less reactive)<\/li>\n\n\n\n<li><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mi>C<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><\/mrow><annotation encoding=\"application\/x-tex\">CO_2<\/annotation><\/semantics><\/math>CO2\u200b: Moderately acidic<\/li>\n\n\n\n<li><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mi>S<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><\/mrow><annotation encoding=\"application\/x-tex\">SO_2<\/annotation><\/semantics><\/math>SO2\u200b: More acidic than CO\u2082 due to higher oxidation state<\/li>\n\n\n\n<li><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><msub><mi>P<\/mi><mn>2<\/mn><\/msub><msub><mi>O<\/mi><mn>5<\/mn><\/msub><\/mrow><annotation encoding=\"application\/x-tex\">P_2O_5<\/annotation><\/semantics><\/math>P2\u200bO5\u200b: Strongly acidic oxide<\/li>\n<\/ul>\n\n\n\n<p>Thus, the correct order is:<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mi>S<\/mi><mi>i<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><mo>&lt;<\/mo><mi>C<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><mo>&lt;<\/mo><mi>S<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><mo>&lt;<\/mo><msub><mi>P<\/mi><mn>2<\/mn><\/msub><msub><mi>O<\/mi><mn>5<\/mn><\/msub><\/mrow><annotation encoding=\"application\/x-tex\">SiO_2 &lt; CO_2 &lt; SO_2 &lt; P_2O_5<\/annotation><\/semantics><\/math>SiO2\u200b&lt;CO2\u200b&lt;SO2\u200b&lt;P2\u200bO5\u200b<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mi>S<\/mi><mi>i<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><mo>&lt;<\/mo><mi>C<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><mo>&lt;<\/mo><mi>S<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><mo>&lt;<\/mo><msub><mi>P<\/mi><mn>2<\/mn><\/msub><msub><mi>O<\/mi><mn>5<\/mn><\/msub><\/mrow><annotation encoding=\"application\/x-tex\">SiO_2 &lt; CO_2 &lt; SO_2 &lt; P_2O_5<\/annotation><\/semantics><\/math>SiO2\u200b&lt;CO2\u200b&lt;SO2\u200b&lt;P2\u200bO5\u200b<\/p>\n\n\n\n<p>Questions like this are extremely common in the <strong>Top 5 p Block Questions<\/strong>, especially in assertion-reason format.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h2 class=\"wp-block-heading\">Question 3: Stability of Hydrides<\/h2>\n\n\n\n<p>Which hydride is the most stable among group 16 hydrides?<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><msub><mi>H<\/mi><mn>2<\/mn><\/msub><mi>O<\/mi><mo separator=\"true\">,<\/mo><mtext>\u2005\u200a<\/mtext><msub><mi>H<\/mi><mn>2<\/mn><\/msub><mi>S<\/mi><mo separator=\"true\">,<\/mo><mtext>\u2005\u200a<\/mtext><msub><mi>H<\/mi><mn>2<\/mn><\/msub><mi>S<\/mi><mi>e<\/mi><mo separator=\"true\">,<\/mo><mtext>\u2005\u200a<\/mtext><msub><mi>H<\/mi><mn>2<\/mn><\/msub><mi>T<\/mi><mi>e<\/mi><\/mrow><annotation encoding=\"application\/x-tex\">H_2O, \\; H_2S, \\; H_2Se, \\; H_2Te<\/annotation><\/semantics><\/math>H2\u200bO,H2\u200bS,H2\u200bSe,H2\u200bTe<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Detailed Explanation<\/h3>\n\n\n\n<p>The stability of hydrides depends on bond strength. As we move down group 16, atomic size increases, and the E\u2013H bond becomes weaker.<\/p>\n\n\n\n<p>Thus:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><msub><mi>H<\/mi><mn>2<\/mn><\/msub><mi>O<\/mi><\/mrow><annotation encoding=\"application\/x-tex\">H_2O<\/annotation><\/semantics><\/math>H2\u200bO has the strongest O\u2013H bond<\/li>\n\n\n\n<li><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><msub><mi>H<\/mi><mn>2<\/mn><\/msub><mi>T<\/mi><mi>e<\/mi><\/mrow><annotation encoding=\"application\/x-tex\">H_2Te<\/annotation><\/semantics><\/math>H2\u200bTe has the weakest bond<\/li>\n<\/ul>\n\n\n\n<p>Therefore, stability decreases down the group.<\/p>\n\n\n\n<p>Order of stability:<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><msub><mi>H<\/mi><mn>2<\/mn><\/msub><mi>O<\/mi><mo>&gt;<\/mo><msub><mi>H<\/mi><mn>2<\/mn><\/msub><mi>S<\/mi><mo>&gt;<\/mo><msub><mi>H<\/mi><mn>2<\/mn><\/msub><mi>S<\/mi><mi>e<\/mi><mo>&gt;<\/mo><msub><mi>H<\/mi><mn>2<\/mn><\/msub><mi>T<\/mi><mi>e<\/mi><\/mrow><annotation encoding=\"application\/x-tex\">H_2O &gt; H_2S &gt; H_2Se &gt; H_2Te<\/annotation><\/semantics><\/math>H2\u200bO&gt;H2\u200bS&gt;H2\u200bSe&gt;H2\u200bTe<\/p>\n\n\n\n<p>This trend is directly mentioned in NCERT and is frequently tested in NEET.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><msub><mi>H<\/mi><mn>2<\/mn><\/msub><mi>O<\/mi><\/mrow><annotation encoding=\"application\/x-tex\">H_2O<\/annotation><\/semantics><\/math>H2\u200bO is the most stable hydride.<\/p>\n\n\n\n<p>This is a classic conceptual question included in the <strong>Top 5 p Block Questions<\/strong>.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Question 4: Basic Nature of Oxides Across a Period<\/h2>\n\n\n\n<p>Which oxide is the most basic among the following?<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mi>N<\/mi><msub><mi>a<\/mi><mn>2<\/mn><\/msub><mi>O<\/mi><mo separator=\"true\">,<\/mo><mtext>\u2005\u200a<\/mtext><mi>M<\/mi><mi>g<\/mi><mi>O<\/mi><mo separator=\"true\">,<\/mo><mtext>\u2005\u200a<\/mtext><mi>A<\/mi><msub><mi>l<\/mi><mn>2<\/mn><\/msub><msub><mi>O<\/mi><mn>3<\/mn><\/msub><mo separator=\"true\">,<\/mo><mtext>\u2005\u200a<\/mtext><mi>S<\/mi><mi>i<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><\/mrow><annotation encoding=\"application\/x-tex\">Na_2O, \\; MgO, \\; Al_2O_3, \\; SiO_2<\/annotation><\/semantics><\/math>Na2\u200bO,MgO,Al2\u200bO3\u200b,SiO2\u200b<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Detailed Explanation<\/h3>\n\n\n\n<p>Across a period, the nature of oxides changes from basic to acidic.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Metals form basic oxides<\/li>\n\n\n\n<li>Metalloids form amphoteric oxides<\/li>\n\n\n\n<li>Non-metals form acidic oxides<\/li>\n<\/ul>\n\n\n\n<p>Analyzing the given compounds:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mi>N<\/mi><msub><mi>a<\/mi><mn>2<\/mn><\/msub><mi>O<\/mi><\/mrow><annotation encoding=\"application\/x-tex\">Na_2O<\/annotation><\/semantics><\/math>Na2\u200bO: Strongly basic<\/li>\n\n\n\n<li><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mi>M<\/mi><mi>g<\/mi><mi>O<\/mi><\/mrow><annotation encoding=\"application\/x-tex\">MgO<\/annotation><\/semantics><\/math>MgO: Basic but weaker than Na\u2082O<\/li>\n\n\n\n<li><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mi>A<\/mi><msub><mi>l<\/mi><mn>2<\/mn><\/msub><msub><mi>O<\/mi><mn>3<\/mn><\/msub><\/mrow><annotation encoding=\"application\/x-tex\">Al_2O_3<\/annotation><\/semantics><\/math>Al2\u200bO3\u200b: Amphoteric<\/li>\n\n\n\n<li><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mi>S<\/mi><mi>i<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><\/mrow><annotation encoding=\"application\/x-tex\">SiO_2<\/annotation><\/semantics><\/math>SiO2\u200b: Acidic<\/li>\n<\/ul>\n\n\n\n<p>Thus, the basic strength decreases as:<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mi>N<\/mi><msub><mi>a<\/mi><mn>2<\/mn><\/msub><mi>O<\/mi><mo>&gt;<\/mo><mi>M<\/mi><mi>g<\/mi><mi>O<\/mi><mo>&gt;<\/mo><mi>A<\/mi><msub><mi>l<\/mi><mn>2<\/mn><\/msub><msub><mi>O<\/mi><mn>3<\/mn><\/msub><mo>&gt;<\/mo><mi>S<\/mi><mi>i<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><\/mrow><annotation encoding=\"application\/x-tex\">Na_2O &gt; MgO &gt; Al_2O_3 &gt; SiO_2<\/annotation><\/semantics><\/math>Na2\u200bO&gt;MgO&gt;Al2\u200bO3\u200b&gt;SiO2\u200b<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mi>N<\/mi><msub><mi>a<\/mi><mn>2<\/mn><\/msub><mi>O<\/mi><\/mrow><annotation encoding=\"application\/x-tex\">Na_2O<\/annotation><\/semantics><\/math>Na2\u200bO is the most basic oxide.<\/p>\n\n\n\n<p>Such trend-based questions are very important in the <strong>Top 5 p Block Questions<\/strong> and are often asked directly.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Question 5: Structure of Silicon Dioxide<\/h2>\n\n\n\n<p>Why does <math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mi>S<\/mi><mi>i<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><\/mrow><annotation encoding=\"application\/x-tex\">SiO_2<\/annotation><\/semantics><\/math>SiO2\u200b exist as a giant covalent (network) structure?<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Detailed Explanation<\/h3>\n\n\n\n<p>Silicon dioxide does not exist as discrete molecules like CO\u2082. Instead, it forms a three-dimensional network structure.<\/p>\n\n\n\n<p>Each silicon atom forms four covalent bonds with oxygen atoms, arranged tetrahedrally. Each oxygen atom further connects two silicon atoms, forming a continuous network.<\/p>\n\n\n\n<p>This leads to:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>High melting point<\/li>\n\n\n\n<li>Hard structure<\/li>\n\n\n\n<li>Insolubility in water<\/li>\n<\/ul>\n\n\n\n<p>This concept is directly explained in NCERT and is often asked in NEET.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mi>S<\/mi><mi>i<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><\/mrow><annotation encoding=\"application\/x-tex\">SiO_2<\/annotation><\/semantics><\/math>SiO2\u200b forms a giant covalent structure due to tetrahedral bonding and network formation.<\/p>\n\n\n\n<p>This is one of the most repeated theory-based questions in the <strong>Top 5 p Block Questions<\/strong>.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Why These Top 5 p Block Questions Are Important for NEET<\/h2>\n\n\n\n<p>The <strong>Top 5 p Block Questions<\/strong> are carefully selected based on repeated NEET PYQs and NCERT importance. Most questions in NEET from p-block:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Are directly based on NCERT lines<\/li>\n\n\n\n<li>Focus on trends, exceptions, and properties<\/li>\n\n\n\n<li>Require strong memory and conceptual clarity<\/li>\n<\/ul>\n\n\n\n<p>If you master these <strong>Top 5 p Block Questions<\/strong>, you can easily solve 80\u201390% of p-block questions in the exam.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">High-Scoring Strategy for p Block Preparation<\/h2>\n\n\n\n<p>To effectively prepare the <strong>Top 5 p Block Questions<\/strong>, follow a smart strategy.<\/p>\n\n\n\n<p>First, read NCERT line-by-line. Every statement in p-block is important. Even small details like color, structure, and reactions can be asked directly.<\/p>\n\n\n\n<p>Second, revise regularly. Since this chapter is memory-based, revision is the key to retention.<\/p>\n\n\n\n<p>Third, focus on trends. Questions are often asked in the form of comparisons, such as acidity, basicity, and stability.<\/p>\n\n\n\n<p>Fourth, avoid unnecessary books. Stick strictly to NCERT, as most of the <strong>Top 5 p Block Questions<\/strong> are derived from it.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Common Mistakes Students Make<\/h2>\n\n\n\n<p>While preparing the <strong>Top 5 p Block Questions<\/strong>, students often make some mistakes.<\/p>\n\n\n\n<p>They try to memorize without understanding trends. This leads to confusion during tricky questions. They also ignore NCERT diagrams and tables, which are frequently tested. Another mistake is not revising regularly, which causes memory loss.<\/p>\n\n\n\n<p>Avoiding these mistakes will significantly improve your performance in p-block chemistry.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">FAQs on Top 5 p Block Questions<\/h2>\n\n\n\n<h3 class=\"wp-block-heading\">Is p-block chemistry easy for NEET?<\/h3>\n\n\n\n<p>Yes, if you prepare NCERT properly, the <strong>Top 5 p Block Questions<\/strong> become very easy and scoring.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">How many questions come from p-block in NEET?<\/h3>\n\n\n\n<p>Usually 2\u20134 questions are asked every year.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Are reactions important in p-block?<\/h3>\n\n\n\n<p>Yes, especially those given in NCERT. Many <strong>Top 5 p Block Questions<\/strong> are reaction-based.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">How to revise p-block quickly before exam?<\/h3>\n\n\n\n<p>Revise NCERT highlights, important trends, and practice the <strong>Top 5 p Block Questions<\/strong> multiple times.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h2 class=\"wp-block-heading\">Conclusion<\/h2>\n\n\n\n<p>The <strong>Top 5 p Block Questions<\/strong> discussed in this article cover the most important and frequently repeated concepts from NCERT. These include anomalous behaviour, oxide trends, hydride stability, and structural properties.<\/p>\n\n\n\n<p>If you consistently revise these <strong>Top 5 p Block Questions<\/strong>, you can confidently attempt p-block questions in NEET and secure easy marks. The key is regular revision and strong conceptual understanding.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Top p Block Questions for NEET The p-block elements chapter is one of the most scoring yet memory-intensive topics in NEET Chemistry. Unlike physical chemistry, this section is completely NCERT-driven, meaning most questions are either directly picked from the NCERT text or slightly modified versions of it. That is exactly why preparing the Top 5 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":4388,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[127,70],"tags":[747,746,744,743,745,742],"class_list":["post-4408","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-free-study-material","category-physics","tag-group-15-16-17-chemistry","tag-important-pyqs-chemistry","tag-ncert-chemistry-questions","tag-p-block-neet","tag-p-block-trends-neet","tag-top-5-p-block-questions"],"blocksy_meta":{"page_structure_type":"type-1","styles_descriptor":{"styles":{"desktop":"","tablet":"","mobile":""},"google_fonts":[],"version":6}},"_links":{"self":[{"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/posts\/4408","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/comments?post=4408"}],"version-history":[{"count":1,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/posts\/4408\/revisions"}],"predecessor-version":[{"id":4409,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/posts\/4408\/revisions\/4409"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/media\/4388"}],"wp:attachment":[{"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/media?parent=4408"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/categories?post=4408"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/tags?post=4408"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}