{"id":4039,"date":"2026-03-31T05:39:16","date_gmt":"2026-03-31T05:39:16","guid":{"rendered":"https:\/\/ksquareinstitute.in\/blog\/?p=4039"},"modified":"2026-04-03T12:42:30","modified_gmt":"2026-04-03T12:42:30","slug":"haloalkanes-and-haloarenes-class-12-pdf","status":"publish","type":"post","link":"https:\/\/ksquareinstitute.in\/blog\/haloalkanes-and-haloarenes-class-12-pdf\/","title":{"rendered":"Haloalkanes and Haloarenes Class 12 PDF: The Ultimate NEET Preparation Guide"},"content":{"rendered":"\n<!DOCTYPE html>\n<html lang=\"en\">\n<head>\n    <meta charset=\"UTF-8\">\n    <meta name=\"viewport\" content=\"width=device-width, initial-scale=1.0\">\n    <link rel=\"preconnect\" href=\"https:\/\/fonts.googleapis.com\">\n    <link rel=\"preconnect\" href=\"https:\/\/fonts.gstatic.com\" crossorigin>\n    <link href=\"https:\/\/fonts.googleapis.com\/css2?family=DM+Sans:ital,opsz,wght@0,9..40,300..600;1,9..40,300..600&#038;family=JetBrains+Mono:wght@400;500;700&#038;family=Plus+Jakarta+Sans:wght@400;600;700;800&#038;display=swap\" rel=\"stylesheet\">\n    <style>\n        :root {\n            --accent: #e8600a;\n            --accent-light: #fff3ec;\n            --accent-mid: #fde3cc;\n            --dark: #111827;\n            --text: #1a1a1a;\n            --text-muted: #4b5563;\n            --border: #e5e7eb;\n            --green-bg: #f0fdf4;\n            --green-border: #16a34a;\n            --blue-bg: #eff6ff;\n            --blue-border: #3b82f6;\n        }\n\n        * { box-sizing: border-box; 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color: white; display: inline-flex; align-items: center; gap: 10px; padding: 12px 24px; border-radius: 8px; text-decoration: none; font-weight: 600; margin-top: 20px; }\n    <\/style>\n<\/head>\n<body>\n\n<div class=\"content-wrapper\">\n    <div class=\"container\">\n\n        <h2><div class=\"badge\">01<\/div><span>Introduction to Haloalkanes and Haloarenes<\/span><\/h2>\n        \n\n        <p>Mastering Organic Chemistry starts with understanding the halogen derivatives of hydrocarbons. This <strong>haloalkanes and haloarenes class 12 pdf<\/strong> guide is designed specifically for NEET aspirants to help them grasp the fundamental mechanisms of substitution and elimination. Haloalkanes (alkyl halides) are compounds where halogen atoms are attached to sp<sup>3<\/sup> hybridized carbon atoms of an alkyl group, while haloarenes (aryl halides) contain halogens attached to sp<sup>2<\/sup> hybridized carbons of an aromatic ring.<\/p>\n\n        <div class=\"card-grid\">\n            <div class=\"card\">\n                <span class=\"card-title\">HALOALKANES<\/span>\n                R-X structure where X is a halogen. Classified as primary (1&deg;), secondary (2&deg;), or tertiary (3&deg;) based on the carbon attachment.\n            <\/div>\n            <div class=\"card\">\n                <span class=\"card-title\">HALOARENES<\/span>\n                Ar-X structure. Characterized by resonance stabilization and lower reactivity towards nucleophilic substitution compared to haloalkanes.\n            <\/div>\n        <\/div>\n\n        <h2><div class=\"badge\">02<\/div><span>Nomenclature and IUPAC Rules<\/span><\/h2>\n        <p>In your <strong>haloalkanes and haloarenes class 12 pdf<\/strong> study, naming compounds accurately is the first step. IUPAC rules prioritize the longest carbon chain containing the halogen. For haloarenes, the parent aromatic ring is named, and the halogen is treated as a substituent with the lowest possible locant.<\/p>\n\n        <div class=\"table-container\">\n            <table>\n                <thead>\n                    <tr>\n                        <th>Structure<\/th>\n                        <th>Common Name<\/th>\n                        <th>IUPAC Name<\/th>\n                    <\/tr>\n                <\/thead>\n                <tbody>\n                    <tr>\n                        <td>CH<sub>3<\/sub>CH<sub>2<\/sub>Br<\/td>\n                        <td>Ethyl bromide<\/td>\n                        <td>Bromoethane<\/td>\n                    <\/tr>\n                    <tr>\n                        <td>CH<sub>3<\/sub>CHClCH<sub>3<\/sub><\/td>\n                        <td>Isopropyl chloride<\/td>\n                        <td>2-Chloropropane<\/td>\n                    <\/tr>\n                    <tr>\n                        <td>C<sub>6<\/sub>H<sub>5<\/sub>Cl<\/td>\n                        <td>Chlorobenzene<\/td>\n                        <td>Chlorobenzene<\/td>\n                    <\/tr>\n                    <tr>\n                        <td>CH<sub>2<\/sub>=CHCH<sub>2<\/sub>I<\/td>\n                        <td>Allyl iodide<\/td>\n                        <td>3-Iodoprop-1-ene<\/td>\n                    <\/tr>\n                <\/tbody>\n            <\/table>\n        <\/div>\n\n        <h2><div class=\"badge\">03<\/div><span>Nature of the C&minus;X Bond<\/span><\/h2>\n        <p>The Carbon-Halogen bond is polar due to the higher electronegativity of halogens. As we move down the group (F to I), the atomic size of the halogen increases, leading to a steady increase in bond length and a decrease in bond enthalpy.<\/p>\n\n        <div class=\"formula-dark\">\n            <span class=\"formula-dark-label\">REACTIVITY TRENDS<\/span>\n            <div class=\"formula-dark-content\">\n                Bond Length: R&minus;F &lt; R&minus;Cl &lt; R&minus;Br &lt; R&minus;I <br>\n                Reactivity Order: R&minus;I &gt; R&minus;Br &gt; R&minus;Cl &gt; R&minus;F\n            <\/div>\n        <\/div>\n\n        <div class=\"callout tip\">\n            <div class=\"callout-pill\">TIP<\/div>\n            The R&minus;I bond is the weakest and most reactive because iodine has the largest size and the lowest bond dissociation enthalpy, making it an excellent leaving group in substitution reactions.\n        <\/div>\n\n        <!-- Promotional Banner 1 -->\n        <a href=\"https:\/\/courses.ksquare.co.in\/new-courses\/3-mission-180-neet-physics-rankers-batch\" target=\"_blank\" rel=\"nofollow noopener noreferrer\" style=\"display:block; margin-bottom:40px;\">\n          <img decoding=\"async\" src=\"https:\/\/ksquareinstitute.in\/blog\/wp-content\/uploads\/2026\/03\/Course-Poromo-Banner-scaled.png\" alt=\"Mission 180 NEET Physics Rankers Batch - KSquare Career Institute\" style=\"width:100%; height:auto; border-radius:10px; display:block;\">\n        <\/a>\n\n        <h2><div class=\"badge\">04<\/div><span>Methods of Preparation for Haloalkanes<\/span><\/h2>\n        <p>Understanding the synthesis pathways is crucial for solving multi-step conversions in any <strong>haloalkanes and haloarenes class 12 pdf<\/strong> resource. The most common method involves the substitution of the hydroxyl group in alcohols.<\/p>\n\n        <div class=\"formula-orange\">\n            <span class=\"formula-orange-label\">FROM ALCOHOLS<\/span>\n            <div class=\"formula-orange-content\">\n                R&minus;OH + SOCl<sub>2<\/sub> &rarr; R&minus;Cl + SO<sub>2<\/sub> + HCl\n            <\/div>\n            <p style=\"font-size: 0.85rem; margin-top: 5px;\">(Thionyl chloride method is preferred as byproducts are gases.)<\/p>\n        <\/div>\n\n        <h3>Key Reactions from Hydrocarbons<\/h3>\n        <ul>\n            <li><strong>Free Radical Halogenation:<\/strong> Alkanes react with X<sub>2<\/sub> in UV light to give a mixture of haloalkanes.<\/li>\n            <li><strong>Electrophilic Addition:<\/strong> Alkenes react with HX. Markovnikov&#8217;s rule applies unless peroxides are present (Kharasch effect).<\/li>\n            <li><strong>Finkelstein Reaction:<\/strong> R&minus;X + NaI &rarr; R&minus;I + NaX (Halogen exchange).<\/li>\n            <li><strong>Swarts Reaction:<\/strong> R&minus;X + AgF &rarr; R&minus;F + AgX (Used for alkyl fluorides).<\/li>\n        <\/ul>\n\n        <h2><div class=\"badge\">05<\/div><span>Preparation of Haloarenes<\/span><\/h2>\n        <p>Unlike haloalkanes, haloarenes are typically prepared by electrophilic substitution of benzene or from diazonium salts. The latter is a high-yield topic for NEET, often referred to as the Sandmeyer reaction.<\/p>\n\n        <div class=\"card-grid\">\n            <div class=\"card\">\n                <span class=\"card-title\">SANDMEYER REACTION<\/span>\n                Aryl diazonium salt + Cu<sub>2<\/sub>Cl<sub>2<\/sub>\/HCl &rarr; Chlorobenzene. This is the most versatile method for preparing aryl halides.\n            <\/div>\n            <div class=\"card\">\n                <span class=\"card-title\">BALZ-SCHIEMANN<\/span>\n                Diazonium fluoroborate is heated to produce fluorobenzene. This is the standard way to introduce fluorine into an aromatic ring.\n            <\/div>\n        <\/div>\n\n        <h2><div class=\"badge\">06<\/div><span>Chemical Reactions: S<sub>N<\/sub>1 vs S<sub>N<\/sub>2 Mechanism<\/span><\/h2>\n        <p>This is the conceptual core of your <strong>haloalkanes and haloarenes class 12 pdf<\/strong> notes. Nucleophilic substitution reactions proceed via two distinct pathways: Unimolecular (S<sub>N<\/sub>1) and Bimolecular (S<sub>N<\/sub>2).<\/p>\n\n        <div class=\"table-container\">\n            <table>\n                <thead>\n                    <tr>\n                        <th>Feature<\/th>\n                        <th>S<sub>N<\/sub>1 Mechanism<\/th>\n                        <th>S<sub>N<\/sub>2 Mechanism<\/th>\n                    <\/tr>\n                <\/thead>\n                <tbody>\n                    <tr>\n                        <td>Kinetics<\/td>\n                        <td>First order: Rate = k[R-X]<\/td>\n                        <td>Second order: Rate = k[R-X][Nu]<\/td>\n                    <\/tr>\n                    <tr>\n                        <td>Intermediate<\/td>\n                        <td>Carbocation formation<\/td>\n                        <td>Transition State (No intermediate)<\/td>\n                    <\/tr>\n                    <tr>\n                        <td>Stereochemistry<\/td>\n                        <td>Racemization<\/td>\n                        <td>Walden Inversion<\/td>\n                    <\/tr>\n                    <tr>\n                        <td>Reactivity<\/td>\n                        <td>3&deg; &gt; 2&deg; &gt; 1&deg;<\/td>\n                        <td>1&deg; &gt; 2&deg; &gt; 3&deg;<\/td>\n                    <\/tr>\n                <\/tbody>\n            <\/table>\n        <\/div>\n\n        <div class=\"callout warning\">\n            <div class=\"callout-pill\">WARN<\/div>\n            Haloarenes are extremely unreactive towards nucleophilic substitution due to: 1. Resonance effect, 2. Difference in hybridization of carbon (sp<sup>2<\/sup> vs sp<sup>3<\/sup>), 3. Instability of phenyl cation.\n        <\/div>\n\n        <!-- Promotional Banner 2 -->\n        <a href=\"https:\/\/ksquareinstitute.in\/neet-2026-rank-predictor\/\" target=\"_blank\" rel=\"nofollow noopener noreferrer\" style=\"display:block; margin-bottom:40px;\">\n          <img decoding=\"async\" src=\"https:\/\/ksquareinstitute.in\/blog\/wp-content\/uploads\/2026\/03\/neet-2026-college-and-rank-predictor-scaled.png\" alt=\"NEET 2026 Rank Predictor - KSquare Career Institute\" style=\"width:100%; height:auto; border-radius:10px; display:block;\">\n        <\/a>\n\n        <h2><div class=\"badge\">07<\/div><span>Elimination and Reaction with Metals<\/span><\/h2>\n        <p>When haloalkanes with &beta;-hydrogen atoms are heated with alcoholic KOH, they undergo &beta;-elimination to form alkenes. The orientation is governed by <strong>Zaitsev\u2019s Rule<\/strong>, which states that the most substituted alkene is the major product.<\/p>\n\n        <div class=\"formula-dark\">\n            <span class=\"formula-dark-label\">WURTZ REACTION<\/span>\n            <div class=\"formula-dark-content\">\n                2R&minus;X + 2Na (Dry Ether) &rarr; R&minus;R + 2NaX\n            <\/div>\n        <\/div>\n\n        <p>For haloarenes, the equivalent reactions are the <strong>Wurtz-Fittig Reaction<\/strong> (alkyl halide + aryl halide) and the <strong>Fittig Reaction<\/strong> (two aryl halides), which produce diphenyl or alkyl-substituted benzenes.<\/p>\n\n        <h2><div class=\"badge\">08<\/div><span>Polyhalogen Compounds and Environmental Impact<\/span><\/h2>\n        <p>Compounds containing more than one halogen atom are widespread in industry but pose significant environmental risks. Mastery of these is a must for any <strong>haloalkanes and haloarenes class 12 pdf<\/strong> tracker.<\/p>\n        \n        <ul>\n            <li><strong>Chloroform (CHCl<sub>3<\/sub>):<\/strong> Used as a solvent; oxidizes to poisonous **Phosgene** gas in air.<\/li>\n            <li><strong>Iodoform (CHI<sub>3<\/sub>):<\/strong> Yellow crystalline solid used as an antiseptic due to liberated iodine.<\/li>\n            <li><strong>Freons (CFCs):<\/strong> Used in aerosols and refrigeration; primary cause of **Ozone Layer Depletion**.<\/li>\n            <li><strong>DDT:<\/strong> A powerful insecticide that is non-biodegradable and highly toxic to wildlife.<\/li>\n        <\/ul>\n\n        <div class=\"internal-links\">\n            <span class=\"internal-links-title\">ENHANCE YOUR NEET PREPARATION<\/span>\n            <a href=\"https:\/\/ksquareinstitute.in\/blog\/neet-physics-survival-kit-2026\/\">NEET Physics Survival Kit 2026<\/a>\n            <a href=\"https:\/\/ksquareinstitute.in\/blog\/organic-chemistry-strategy-neet\/\">Organic Chemistry Strategy for NEET<\/a>\n            <a href=\"https:\/\/ksquareinstitute.in\/blog\/neet-biology-tricks-for-exams\/\">NEET Biology Tricks for Exams<\/a>\n            <a href=\"https:\/\/ksquareinstitute.in\/blog\/score-340-in-neet-biology\/\">How to Score 340 in NEET Biology<\/a>\n            <a href=\"https:\/\/ksquareinstitute.in\/blog\/top-10-tricky-neet-biology-diagrams\/\">Top 10 Tricky Biology Diagrams<\/a>\n        <\/div>\n\n        <div class=\"revision-box\">\n            <h3>Quick Revision Sheet<\/h3>\n            <ul>\n                <li><strong>Reactivity:<\/strong> 3&deg; &gt; 2&deg; &gt; 1&deg; for S<sub>N<\/sub>1; 1&deg; &gt; 2&deg; &gt; 3&deg; for S<sub>N<\/sub>2.<\/li>\n                <li><strong>S<sub>N<\/sub>1:<\/strong> Polar protic solvents; S<sub>N<\/sub>2: Polar aprotic solvents.<\/li>\n                <li><strong>Finkelstein:<\/strong> Uses NaI in acetone for alkyl iodides.<\/li>\n                <li><strong>Swarts:<\/strong> Uses metallic fluorides for alkyl fluorides.<\/li>\n                <li><strong>Zaitsev Rule:<\/strong> Favours highly substituted alkenes in &beta;-elimination.<\/li>\n                <li><strong>Sandmeyer:<\/strong> Diazonium salt + Cu<sub>2<\/sub>X<sub>2<\/sub>\/HX &rarr; Haloarene.<\/li>\n                <li><strong>Grignard Reagent:<\/strong> R&minus;MgX; forms R&minus;H when reacted with H<sub>2<\/sub>O.<\/li>\n                <li><strong>DDT:<\/strong> p,p&#8217;-Dichlorodiphenyltrichloroethane.<\/li>\n                <li><strong>Iodoform Test:<\/strong> Identifies CH<sub>3<\/sub>CH(OH)&minus; or CH<sub>3<\/sub>CO&minus; groups.<\/li>\n            <\/ul>\n            <a href=\"#\" class=\"download-btn\" rel=\"nofollow noopener noreferrer\">\n                <span>Download Haloalkanes Notes PDF<\/span>\n            <\/a>\n        <\/div>\n\n        <h2><div class=\"badge\">09<\/div><span>Frequently Asked Questions<\/span><\/h2>\n        <div class=\"faq-container\">\n            <details>\n                <summary>\n                    <span>Why is the dipole moment of chlorobenzene lower than cyclohexyl chloride?<\/span>\n                    <div class=\"toggle-icon\">\n                        <svg viewBox=\"0 0 24 24\"><path class=\"plus-path\" d=\"M12 5v14M5 12h14\"\/><path class=\"minus-path\" d=\"M5 12h14\"\/><\/svg>\n                    <\/div>\n                <\/summary>\n                <div class=\"faq-answer\">In chlorobenzene, the C-Cl bond carbon is sp<sup>2<\/sup> hybridized, making it more electronegative and less polar than the sp<sup>3<\/sup> carbon in cyclohexyl chloride. Additionally, resonance in haloarenes results in a partial double bond character, shortening the bond and reducing the dipole moment.<\/div>\n            <\/details>\n            <details>\n                <summary>\n                    <span>What is an ambident nucleophile? Give an example.<\/span>\n                    <div class=\"toggle-icon\">\n                        <svg viewBox=\"0 0 24 24\"><path class=\"plus-path\" d=\"M12 5v14M5 12h14\"\/><path class=\"minus-path\" d=\"M5 12h14\"\/><\/svg>\n                    <\/div>\n                <\/summary>\n                <div class=\"faq-answer\">Ambident nucleophiles are species that have two different atoms through which they can coordinate with the electrophile. Example: CN<sup>&minus;<\/sup> (can attack via C to form nitriles or via N to form isonitriles) and NO<sub>2<\/sub><sup>&minus;<\/sup>.<\/div>\n            <\/details>\n            <details>\n                <summary>\n                    <span>Explain Walden Inversion with respect to S<sub>N<\/sub>2 reactions.<\/span>\n                    <div class=\"toggle-icon\">\n                        <svg viewBox=\"0 0 24 24\"><path class=\"plus-path\" d=\"M12 5v14M5 12h14\"\/><path class=\"minus-path\" d=\"M5 12h14\"\/><\/svg>\n                    <\/div>\n                <\/summary>\n                <div class=\"faq-answer\">In an S<sub>N<\/sub>2 reaction, the nucleophile attacks from the side opposite to the leaving group. As the leaving group departs, the configuration of the carbon atom flips like an umbrella in a strong wind, resulting in an inverted product.<\/div>\n            <\/details>\n            <details>\n                <summary>\n                    <span>Why are Grignard reagents prepared under anhydrous conditions?<\/span>\n                    <div class=\"toggle-icon\">\n                        <svg viewBox=\"0 0 24 24\"><path class=\"plus-path\" d=\"M12 5v14M5 12h14\"\/><path class=\"minus-path\" d=\"M5 12h14\"\/><\/svg>\n                    <\/div>\n                <\/summary>\n                <div class=\"faq-answer\">Grignard reagents (R&minus;MgX) are highly reactive and act as strong bases. They react instantly with even traces of moisture to form hydrocarbons (R&minus;H + Mg(OH)X), destroying the reagent.<\/div>\n            <\/details>\n            <details>\n                <summary>\n                    <span>What is the Iodoform test used for?<\/span>\n                    <div class=\"toggle-icon\">\n                        <svg viewBox=\"0 0 24 24\"><path class=\"plus-path\" d=\"M12 5v14M5 12h14\"\/><path class=\"minus-path\" d=\"M5 12h14\"\/><\/svg>\n                    <\/div>\n                <\/summary>\n                <div class=\"faq-answer\">The iodoform test identifies the presence of methyl ketones (CH<sub>3<\/sub>CO&minus;) or secondary alcohols containing a methyl group (CH<sub>3<\/sub>CH(OH)&minus;). A positive test results in the formation of a yellow precipitate of iodoform (CHI<sub>3<\/sub>).<\/div>\n            <\/details>\n            <details>\n                <summary>\n                    <span>Why is thionyl chloride preferred for preparing alkyl chlorides?<\/span>\n                    <div class=\"toggle-icon\">\n                        <svg viewBox=\"0 0 24 24\"><path class=\"plus-path\" d=\"M12 5v14M5 12h14\"\/><path class=\"minus-path\" d=\"M5 12h14\"\/><\/svg>\n                    <\/div>\n                <\/summary>\n                <div class=\"faq-answer\">When thionyl chloride (SOCl<sub>2<\/sub>) reacts with alcohols, the byproducts (SO<sub>2<\/sub> and HCl) are gases and escape easily, leaving behind pure alkyl chloride without the need for complex purification.<\/div>\n            <\/details>\n        <\/div>\n\n        <div class=\"cta-section\">\n            <h2>Accelerate Your NEET preparation with KSquare<\/h2>\n            <p>Mastering Haloalkanes and Haloarenes is a vital milestone for your medical career. Join KSquare Institute&#8217;s Mission 180 Rankers Batch to access expert-led lessons, high-yield practice modules, and real-time doubt clearing tailored for success.<\/p>\n            <div class=\"cta-buttons\">\n                <a href=\"https:\/\/courses.ksquare.co.in\/new-courses\/3-mission-180-neet-physics-rankers-batch\" class=\"btn btn-white\" target=\"_blank\" rel=\"nofollow noopener noreferrer\">Join Rankers Batch<\/a>\n                <a href=\"https:\/\/ksquareinstitute.in\/free-study-material\/\" class=\"btn btn-outline\" target=\"_blank\" rel=\"nofollow noopener noreferrer\">Get Free Study Material<\/a>\n            <\/div>\n        <\/div>\n    <\/div>\n<\/div>\n\n<\/body>\n<\/html>\n\n\n\n<!DOCTYPE html>\n<html lang=\"en\">\n<head>\n  <meta charset=\"UTF-8\">\n  <meta name=\"viewport\" content=\"width=device-width, initial-scale=1.0\">\n  <title>Table of Contents \u2014 Chemistry Class 12<\/title>\n  \n  <!-- Google Fonts Import -->\n  <link rel=\"preconnect\" href=\"https:\/\/fonts.googleapis.com\">\n  <link rel=\"preconnect\" href=\"https:\/\/fonts.gstatic.com\" crossorigin>\n  <link href=\"https:\/\/fonts.googleapis.com\/css2?family=DM+Sans:ital,opsz,wght@0,9..40,100..1000;1,9..40,100..1000&#038;family=Plus+Jakarta+Sans:ital,wght@0,200..800;1,200..800&#038;display=swap\" rel=\"stylesheet\">\n  \n  <style>\n    \/* Scoped wrapper using a unique ID (#chemistry-toc-wrapper).\n       This ensures these styles do not leak and affect other parts of your website.\n    *\/\n    #chemistry-toc-wrapper {\n      font-family: 'DM Sans', sans-serif;\n      width: 100%;\n      margin: 0;\n      padding: 60px 0;\n      color: #111;\n      background: #fff;\n      -webkit-font-smoothing: antialiased;\n    }\n\n    #chemistry-toc-wrapper .container-inner {\n      width: 100%;\n      margin: 0 auto;\n      padding: 0; \/* Edge-to-edge layout *\/\n    }\n\n    #chemistry-toc-wrapper h1 {\n      font-family: 'Plus Jakarta Sans', sans-serif;\n      font-size: 0.85rem;\n      font-weight: 700;\n      color: #71717a;\n      margin: 0 0 8px;\n      letter-spacing: 0.1em;\n      text-transform: uppercase;\n      padding-left: 16px; \n    }\n\n    #chemistry-toc-wrapper h2 {\n      font-family: 'Plus Jakarta Sans', sans-serif;\n      font-size: 2.25rem;\n      font-weight: 800;\n      margin: 0 0 48px;\n      letter-spacing: -0.02em;\n      color: #09090b;\n      padding-left: 16px;\n    }\n\n    #chemistry-toc-wrapper table {\n      width: 100%;\n      border-collapse: collapse;\n      border-spacing: 0;\n      border-top: 1px solid #e4e4e7;\n      border-bottom: 1px solid #e4e4e7;\n    }\n\n    #chemistry-toc-wrapper tr {\n      border-bottom: 1px solid #e4e4e7;\n      transition: all 0.2s ease;\n    }\n\n    #chemistry-toc-wrapper tr:hover {\n      background-color: #f8fafc;\n    }\n\n    #chemistry-toc-wrapper tr:last-child {\n      border-bottom: none;\n    }\n\n    #chemistry-toc-wrapper td {\n      padding: 24px 16px;\n      vertical-align: middle;\n      font-size: 1.05rem;\n      font-weight: 500;\n      border-right: 1px solid #e4e4e7; \/* Column borders as per reference image *\/\n    }\n\n    #chemistry-toc-wrapper td:last-child {\n      border-right: none;\n    }\n\n    \/* Column 1: Index Numbers *\/\n    #chemistry-toc-wrapper td:first-child {\n      color: #a1a1aa;\n      font-size: 0.9rem;\n      width: 70px;\n      font-weight: 400;\n      font-variant-numeric: tabular-nums;\n      text-align: center;\n      padding-left: 10px;\n    }\n\n    \/* Column 2: Chapter Titles *\/\n    #chemistry-toc-wrapper td:nth-child(2) {\n      padding-left: 32px; \/* Breathing room before chapter text *\/\n      color: #18181b;\n    }\n\n    \/* Column 3: Action Button *\/\n    #chemistry-toc-wrapper td:last-child {\n      text-align: right;\n      width: 180px;\n      padding-right: 24px; \/* Space after the button *\/\n    }\n\n    \/* Premium Button Styling *\/\n    #chemistry-toc-wrapper a.go {\n      display: inline-block;\n      font-family: 'Plus Jakarta Sans', sans-serif;\n      font-size: 0.75rem;\n      font-weight: 800;\n      padding: 12px 24px;\n      border: 1.5px solid #18181b;\n      border-radius: 8px;\n      color: #18181b;\n      text-decoration: none;\n      letter-spacing: 0.05em;\n      text-transform: uppercase;\n      transition: all 0.2s cubic-bezier(0.4, 0, 0.2, 1);\n      white-space: nowrap;\n    }\n\n    #chemistry-toc-wrapper a.go:hover {\n      background: #18181b;\n      color: #ffffff;\n      transform: translateY(-2px);\n      box-shadow: 0 4px 12px rgba(24, 24, 27, 0.15);\n    }\n\n    \/* Responsive Logic *\/\n    @media (max-width: 768px) {\n      #chemistry-toc-wrapper h2 {\n        font-size: 1.75rem;\n        margin-bottom: 32px;\n        padding-left: 12px;\n      }\n      #chemistry-toc-wrapper td {\n        padding: 18px 12px;\n        font-size: 0.95rem;\n      }\n      #chemistry-toc-wrapper td:nth-child(2) {\n        padding-left: 16px;\n      }\n    }\n  <\/style>\n<\/head>\n<body>\n\n<div id=\"chemistry-toc-wrapper\">\n  <div class=\"container-inner\">\n    <h1>Table of Contents<\/h1>\n    <h2>Chemistry &mdash; Class 12<\/h2>\n    \n    <table>\n      <tr><td>01<\/td><td>Solutions<\/td><td><a class=\"go\" href=\"https:\/\/ksquareinstitute.in\/blog\/solutions-chemistry-class-12-notes-pdf\" target=\"_blank\">Go to page<\/a><\/td><\/tr>\n      <tr><td>02<\/td><td>Electrochemistry<\/td><td><a class=\"go\" href=\"https:\/\/ksquareinstitute.in\/blog\/electrochemistry-class-12-notes-pdf\" target=\"_blank\">Go to page<\/a><\/td><\/tr>\n      <tr><td>03<\/td><td>Chemical Kinetics<\/td><td><a class=\"go\" href=\"https:\/\/ksquareinstitute.in\/blog\/chemical-kinetics-class-12-notes-pdf\" target=\"_blank\">Go to page<\/a><\/td><\/tr>\n      <tr><td>04<\/td><td>d- and f-Block Elements<\/td><td><a class=\"go\" href=\"https:\/\/ksquareinstitute.in\/blog\/d-and-f-block-elements-class-12-pdf\" target=\"_blank\">Go to page<\/a><\/td><\/tr>\n      <tr><td>05<\/td><td>Coordination Compounds<\/td><td><a class=\"go\" href=\"https:\/\/ksquareinstitute.in\/blog\/coordination-compounds-class-12-pdf\" target=\"_blank\">Go to page<\/a><\/td><\/tr>\n      <tr><td>06<\/td><td>Haloalkanes and Haloarenes<\/td><td><a class=\"go\" href=\"https:\/\/ksquareinstitute.in\/blog\/haloalkanes-and-haloarenes-class-12-pdf\" target=\"_blank\">Go to page<\/a><\/td><\/tr>\n      <tr><td>07<\/td><td>Alcohols, Phenols and Ethers<\/td><td><a class=\"go\" href=\"https:\/\/ksquareinstitute.in\/blog\/alcohols-phenols-ethers-class-12-pdf\" target=\"_blank\">Go to page<\/a><\/td><\/tr>\n      <tr><td>08<\/td><td>Aldehydes, Ketones and Carboxylic Acids<\/td><td><a class=\"go\" href=\"https:\/\/ksquareinstitute.in\/blog\/aldehydes-ketones-carboxylic-acids-class-12\" target=\"_blank\">Go to page<\/a><\/td><\/tr>\n      <tr><td>09<\/td><td>Amines<\/td><td><a class=\"go\" href=\"https:\/\/ksquareinstitute.in\/blog\/amines-class-12-notes-pdf\" target=\"_blank\">Go to page<\/a><\/td><\/tr>\n      <tr><td>10<\/td><td>Biomolecules<\/td><td><a class=\"go\" href=\"https:\/\/ksquareinstitute.in\/blog\/biomolecules-class-12-chemistry\" target=\"_blank\">Go to page<\/a><\/td><\/tr>\n    <\/table>\n  <\/div>\n<\/div>\n\n<\/body>\n<\/html>\n","protected":false},"excerpt":{"rendered":"<p>01 Introduction to Haloalkanes and Haloarenes Mastering Organic Chemistry starts with understanding the halogen derivatives of hydrocarbons. This haloalkanes and haloarenes class 12 pdf guide is designed specifically for NEET aspirants to help them grasp the fundamental mechanisms of substitution and elimination. Haloalkanes (alkyl halides) are compounds where halogen atoms are attached to sp3 hybridized [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[127],"tags":[367,363,364,365,366],"class_list":["post-4039","post","type-post","status-publish","format-standard","hentry","category-free-study-material","tag-class-12-chemistry-haloalkanes-haloarenes","tag-haloalkanes-and-haloarenes-class-12-pdf","tag-haloalkanes-notes-class-12","tag-haloarenes-reactions-notes","tag-sn1-sn2-mechanism-class-12"],"blocksy_meta":{"page_structure_type":"type-1","styles_descriptor":{"styles":{"desktop":"","tablet":"","mobile":""},"google_fonts":[],"version":6}},"_links":{"self":[{"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/posts\/4039","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/comments?post=4039"}],"version-history":[{"count":2,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/posts\/4039\/revisions"}],"predecessor-version":[{"id":4248,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/posts\/4039\/revisions\/4248"}],"wp:attachment":[{"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/media?parent=4039"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/categories?post=4039"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ksquareinstitute.in\/blog\/wp-json\/wp\/v2\/tags?post=4039"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}